10x^2-5x+8/5x^2+9x-19=2

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Solution for 10x^2-5x+8/5x^2+9x-19=2 equation: 



10x^2-5x+8/5x^2+9x-19=2

We move all terms to the left:

10x^2-5x+8/5x^2+9x-19-(2)=0



Domain of the equation: 5x^2!=0

x^2!=0/5

x^2!=√0

x!=0

x∈R



We add all the numbers together, and all the variables

10x^2+4x+8/5x^2-21=0

We multiply all the terms by the denominator


10x^2*5x^2+4x*5x^2-21*5x^2+8=0

Wy multiply elements

50x^4+20x^3-105x^2+8=0

We do not support expression: x^4

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